Tuesday, August 8, 2017

August 08, 2017 Tuesday

Bedtime Story 


A More Rigorous Version of Tarski’s Undefinability Theorem


Earlier, if you recall, I had told you that I would be discussing a simplified and a non-formal version of Tarski’s undefinability theorem.

Now let us consider the stronger theorem that Tarski actually proved.

This theorem is applicable to any formal language that has negation and wherein the diagonal lemma holds true.

Stating diagonal lemma is complicated to say the least.

It should suffice for us that this lemma or theorem establishes the existence of self-referential sentences in some formal theories of natural numbers.

Proving the fundamental limitations of Gödel’s incompleteness theorems and Tarski’s undefinability theorem becomes possible in those systems wherein the diagonal lemma is applicable.

First-order arithmetic has both negation and also a system where the diagonal lemma holds true.

The interpreted formal language is defined as (L,N) as we did previously.

The Gödel number is g(x) as assigned before.

For every L-formula A(x) there is a formula B such that
B ↔ A(g(B)) holds.

This left right arrow represents biconditional logical connective or if and only if.

Let T* represent the set of Gödel numbers of L-sentences true in N.

With all this framework of his work, the theorem that Tarski derived was this:

There is no L-formula True(n) that defines T*.

This means to say that there is no L-formula True(n) such that for every L-formula A, True(g(A)) ↔ A holds.

I will not go too much into the proof.

Very briefly, the proof is obtained by using the good old argument of reductio ad absurdum.

In this trick one starts with an assumption and then showing that if it were to be true, it would lead to absurd conclusions which is a proof that it has to be false.

So Tarski begins his proof with the assumption that L-formula True(n) defines T*.

He considered a sentence A of arithmetic.

If the sentence A is true in N, then True(g(A)) holds in N.

Then for all A, the Tarski T-sentence True(g(A)) ↔ A is true in N.

We had agreed that diagonal lemma is applicable to first-order arithmetic.

Diagonal lemma when applied to this theorem gives a result that is contrary to the above equivalence.

Stay tuned to the voice of an average story storytelling chimpanzee or login at http://panarrans.blogspot.com
                              
Good night mon ami and my fellow cousin ape.
                           
  
                

             












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Another great educator and a teacher that I am aware of is Professor Subhashish Chattopadhyay in Bangalore, India.

While I narrate stories, Professor Subhashish an electronic engineer and a former professor at BARC, does and teaches real mathematics and physics.

He started the participation of Indian students at the International Physics Olympiad.

Do visit him here:


All his books can be downloaded for free through this link:


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